Do you need a **voltage divider calculator**? It uses ours and automatically calculates values such as equivalent resistance, current flowing through the circuit, voltage drops, output voltage and power.

If you need more **voltage divider information**Read on because we will show you the formula, solved exercises and more.

Article sections

## What is a voltage divider?

A voltage divider is a circuit used to divide an electrical voltage between one or more resistors connected in series.

The simplest voltage divider circuit is the one below. In it you can see a voltage source (Vcc) that divides its voltage between resistors Rs (V1) and R2 to which corresponds a voltage value V2.

Since we have a series connection of resistors, the current flowing through them is the same but the voltage is distributed. Due to this configuration, we can calculate an equivalent circuit in which **there is only a single resistance Req** which will be the equivalent resistance of all the resistors connected in series.

## Voltage divider formulas

Since there are quite a few variables involved in the voltage divider, let's look at all the variables involved in the voltage divider. **formulas for calculating different voltages, resistances, powers and currents**.

**Resistors**

The **equivalent resistance (Req) of a voltage divider** is measured in Ohms is calculated as follows:

Req = R1 + R2

**Intensity**

**The current is the same at all points of the circuit.** by the series configuration of the impedances or currents.

In case we do not know its value, we can calculate the current in a voltage divider with this formula:

I = Vin / (R1 + R2)

Basically what we do is to divide the input voltage by the value of the equivalent resistance (R1 + R2).

**Voltages**

As this is a series configuration, **each resistive element will have a different voltage drop** based on their value.

We have the value of R1 and R2 as well as the value of the current, therefore, we apply the Ohm's Law and we are left with:

V1 = I x R1

V2 = I x R2

As for the **output voltage or Vout,** we obtain its value with the following formula:

Vout = R1 x Vin / (R1 + R2)

Pay attention to the placement of the name of the resistors in the circuit to avoid making mistakes.

Now that you know how to calculate all the unknowns at the different points of the circuit, you are able to **solve any voltage divider even with three resistors** or more resistive elements. Anyway, if you have any doubt, write us a comment and we will help you to solve your questions.

## Solved exercises of the voltage divider

We are going to see a **example of voltage divider with a solved exercise** in which we are asked to calculate:

- The output voltage (Vout)
- The current flowing in the circuit (I)
- The voltage drop of each resistor (V1 and V2)

First of all we are going to **calculate the Intensity**:

I = Vin / (R1 + R2) = 20V / (9000 Ω + 1000 Ω) = 0.002 A = 2 mA

The following **calculate the voltage drop of each resistor**:

V1 = I x R1 = 2 mA x 9 KΩ = 18 V

V2 = I x R2 = 2 mA x 1 KΩ = 2 V

If you notice, V1 + V2 is equal to the input voltage so it is already a clue that we are solving the **voltage divider exercise** correctly.

Finally, we calculate the output voltage Vout:

Vout = 1 KΩ x 20V / (9 KΩ + 1 KΩ) = 1 KΩ x 20V / 10 KΩ = 2V

## Voltage divider calculator

The **voltage division calculator** allows you to automatically solve exercises by simply entering the values of the input voltage in Volts and the resistors R1 and R2 in Ohms.

After pressing the calculate button you will automatically obtain values such as current, equivalent resistance, V1, V2, Vout and power values for each resistor.

If you have any questions, write us and we will help you!

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Good day. Referring to the exercise of the calculation of Vout, they took as a value of R1 1 K ohm, but really is 9 K ohms, so the result of 2v is not adequate, x your attention thank you very much.

Hello Martin,

Note that the name of the resistors is reversed in the theoretical section and in the example, so the data we have calculated are correct.

Greetings!

Hi, I'm sorry to bother you with this question, it's just that thinking about it generated so much doubt in my mind that I couldn't answer it by myself.

Let me put you in situation: I have a voltage divider of 36 V, 6 kΩ and 3 kΩ in parallel. Why if I measure it with tevenin's theorem I get that the current is 6 μA and if I solve it without the theorem I get that it is 4μA? What I do is add the resistors and divide by the voltage, so I don't know where the problem should be.

In any case, thank you in advance

I see that the calculator is designed to obtain a voltage value based on the value of resistors whose value is already known, but the interesting thing would be that knowing the initial input voltage and output voltage required to calculate the value of the resistors, to see if you can, greetings.